A committee is composed of \(w\) women and \(m\) men. If \(3\) women and \(2\) men are added to the committee, and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by
(A) \(\dfrac{w}{m}\)
(B) \(\dfrac{w}{w+m}\)
(C) \(\dfrac{w+3}{m+2}\)
(D) \(\dfrac{w+3}{w+m+3}\)
(E) \(\dfrac{w+3}{w+m+5}\)
Answer: E
Source: Official Guide
A committee is composed of \(w\) women and \(m\) men. If \(3\) women and \(2\) men are added to the committee, and if on
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A committee is composed of w women and m men. If 3 women and 2 men are added to the committee . . .Gmat_mission wrote: ↑Sun Sep 19, 2021 12:04 pmA committee is composed of \(w\) women and \(m\) men. If \(3\) women and \(2\) men are added to the committee, and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by
(A) \(\dfrac{w}{m}\)
(B) \(\dfrac{w}{w+m}\)
(C) \(\dfrac{w+3}{m+2}\)
(D) \(\dfrac{w+3}{w+m+3}\)
(E) \(\dfrac{w+3}{w+m+5}\)
Answer: E
Source: Official Guide
After the 3 women and 2 men are added, we have...
w+3 women and m+2 men
. . . and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by
P(select woman) = (# of women in committee)/(TOTAL # of people on committee)
= (w+3)/(w+3 + m+2 )
= (w+3)/(w+m+5)
Answer: E
Cheers,
Brent